电力系统导论实验报告.docx
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电力系统导论实验报告.docx
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电力系统导论实验报告
课程名称:
电力系统导论(双语)
学院:
信息工程学院
专业班级:
电力系统
学号:
学生姓名:
Contents
1、Experiment11
BusAdmittanceMatrix1-9
2、Experiment29
BusImpedanceMatrix9-23
3、Experiment323
Gauss-Seidelandnewtonmethod23-26
4、personalsummary26
Experiment1
BusAdmittanceMatrix
1.Objective
•TowriteasimpleprograminMATLAB®forthealgorithmofbusadmittancematrix.
2.Discussion
BusAdmittancematrix
Thenode-voltageequationofann-buspowersystemcanbewritteninmatrixformas
(1)
Or
(2)
WhereIbusisthecolumnvectoroftheinjectedbuscurrents.Vbusisthecolumnvectorofbusvoltagesmeasuredfromthereferencenode.Ybusisknownasthebusadmittancematrix.
Calculationmethod:
1.Thediagonalelementofeachnodeisthesumofadmittancesconnectedtoit.Itisknownastheself-admittanceordrivingpointadmittance,i.e.,
(3)
2.Theoff-diagonalelementisequaltothenegativeoftheadmittancebetweenthenodes.Itisknownasthemutualadmittanceortransferadmittance,i.e.
(4)
Result:
Baseontheequations(3)and(4),thealgorithmofbusadmittancematrixcanbeusedtobuildthebusadmittancematrix(Ybus).
3.Mathmaticsmodel
Themathematicsmodelsofpowersystemelementsaretwokinds,oneistransmissionlineorcableandanotheristransformer,andtheyareequivalentintopitypeequivalentcircuit,anddescribedasfollowing:
1)Transmissionlineorcable
AccordingtothePisectionalcircuitoftransmissionlineorcable,wecangettheelementsofnodalAdmittancematrixvalue,asthefollowing
Figure:
Thepisectionequivalentcircuitoftransmissionlineorcable
(5)
(6)
(7)
(8)
2)transformer
Asshowasthetransformercircuit,wehave
(9)
(10)
Accordingtoequations(10)and(9),wehave
(11)
(12)
Figure:
thePisectionequivalentcircuitofTransformer
Assume
(13)
(14)
(15)
(16)
4.SystemRequirement
ComputerwithMATLAB®6oraboveinstalled.
5.Procedure
1.0LaunchtheMATLABprogram.
2.0GotoFILENEWM-file.
3.0WriteafunctionY=The_Node_Admittance_Matrix(TopoStructureAndBranchPara)fortheformationofthebusadmittancematrix.
4.0TopoStructureAndBranchParaisthetransmissionline,cableandtransformerinputdataandcontainsfivecolumnsparameters.Thefirsttwocolumnsarethelinebusnumbersandtheremainingcolumnscontainthelineresistanceandreactanceinper-unitandtransformertapratioorcapacitoroftransmissionline.
5.0Thefunctionshouldreturnthebusadmittancematrix.
6.Exercises
Usethewrittenfunction,Y=The_Node_Admittance_Matrix(TopoStructureAndBranchPara)toobtaintheYbusofthefollowingpowersystemnetwork:
Q1.YouarerequiredtowritetheYbustopologicalstructureandparameterintoatextfile.(Hint:
usethematlabtextcompilertowritedownthetable1data,usingthecommatoseparatetheparameters,andsaveitusethenameof4_Power_System_Data.dbf)
Q2.Youarerequiredtowriteouttheprogramflowfigureofforminganodaladmittancematrix.
Hint.YouarerequiredtocompileaprogramtoformtheYbusMatrix,thefollowingprogramisareferenceprogramtoyou.
Figure:
One-linediagramofpowersystem
Forexample,fromthetextbook“powersystemanalysis”No.2edition3onpage61~62
Table1:
TransformerandtransmissssionLinedata
FromBus#
ToBus#
R(p.u)
X(p.u)
B(p.u)orratioK
Others
1
2
0.1
0.4
j0.01528
1
3
0
0.3
1.1
1
4
0.12
0.5
j0.01920
2
4
0.08
0.40
J0.01413
7.Theflowchart
Figure:
TheflowchartofFormingNodalAdmittanceMatrix
程序是:
%functionOutPut=The_Node_Admittance_Matrix(handles)
%isasubroutineofPowerSystemCalculation
functionOutPut=The_Node_Admittance_Matrix(handles)
%thefollowingprogramisopenadatafileandgettheNumberof
%NodeandBranchdatatoformanodaladdmittancematrix
%thefollowingcodeisopenafileandreadthedataofpowersystemnetwork
[fname,pname]=uigetfile('*.dbf','Selectthenetworkparametredata-file');
TopoStructureAndBranchPara=csvread(fname);
[NumberOfBranch,NumberOfPara]=size(TopoStructureAndBranchPara);
Temporary1=max(TopoStructureAndBranchPara(:
1));
Temporary2=max(TopoStructureAndBranchPara(:
2));
ifTemporary1>Temporary2
NumberOfNode=Temporary1;
else
NumberOfNode=Temporary2;
end
%ThefollowingprogramistoformtheNodalAdmittanceMatrix
%andtheTopologicstructureandBranchParametresarearranged
%I,J,R,X,C/K,andpayattentiontotheinpedenceoftransformerisinthe
%sideofNodeJandtheratiooftransformer1:
KisinthesideofNodeI
forCircleNumber1=1:
NumberOfBranch
forCircleNumber2=1:
NumberOfBranch
NodalAdmittanceMatrix(CircleNumber1,CircleNumber2)=0;
end
end
forCircleNumber=1:
NumberOfBranch
ifTopoStructureAndBranchPara(CircleNumber,5)>0.85
NodalAdmittanceMatrix(TopoStructureAndBranchPara(TopoStructureAndBranchPara(CircleNumber,1),TopoStructureAndBranchPara(CircleNumber,1)))=...
NodalAdmittanceMatrix(TopoStructureAndBranchPara(TopoStructureAndBranchPara(CircleNumber,1),TopoStructureAndBranchPara(CircleNumber,1)))+...
TopoStructureAndBranchPara(CircleNumber,5)^2/...
(TopoStructureAndBranchPara(CircleNumber,3)+...
j*TopoStructureAndBranchPara(CircleNumber,4));
NodalAdmittanceMatrix(TopoStructureAndBranchPara(CircleNumber,2),TopoStructureAndBranchPara(CircleNumber,2))=...
NodalAdmittanceMatrix(TopoStructureAndBranchPara(CircleNumber,2),TopoStructureAndBranchPara(CircleNumber,2))+...
1/((TopoStructureAndBranchPara(CircleNumber,3)+j*TopoStructureAndBranchPara(CircleNumber,4)));
NodalAdmittanceMatrix(TopoStructureAndBranchPara(CircleNumber,1),TopoStructureAndBranchPara(CircleNumber,2))=...
NodalAdmittanceMatrix(TopoStructureAndBranchPara(CircleNumber,1),TopoStructureAndBranchPara(CircleNumber,2))...
-TopoStructureAndBranchPara(CircleNumber,5)/...
((TopoStructureAndBranchPara(CircleNumber,3)+j*TopoStructureAndBranchPara(CircleNumber,4)));
NodalAdmittanceMatrix(TopoStructureAndBranchPara(CircleNumber,2),TopoStructureAndBranchPara(CircleNumber,1))=...
NodalAdmittanceMatrix(TopoStructureAndBranchPara(CircleNumber,1),TopoStructureAndBranchPara(CircleNumber,2));
else
NodalAdmittanceMatrix(TopoStructureAndBranchPara(CircleNumber,1),TopoStructureAndBranchPara(CircleNumber,1))=...
NodalAdmittanceMatrix(TopoStructureAndBranchPara(CircleNumber,1),TopoStructureAndBranchPara(CircleNumber,1))+...
+1/(TopoStructureAndBranchPara(CircleNumber,3)+...
j*TopoStructureAndBranchPara(CircleNumber,4))+j*TopoStructureAndBranchPara(CircleNumber,5);
NodalAdmittanceMatrix(TopoStructureAndBranchPara(CircleNumber,2),TopoStructureAndBranchPara(CircleNumber,2))=...
NodalAdmittanceMatrix(TopoStructureAndBranchPara(CircleNumber,2),TopoStructureAndBranchPara(CircleNumber,2))+...
+1/(TopoStructureAndBranchPara(CircleNumber,3)+...
j*TopoStructureAndBranchPara(CircleNumber,4))+j*TopoStructureAndBranchPara(CircleNumber,5)
NodalAdmittanceMatrix(TopoStructureAndBranchPara(CircleNumber,1),TopoStructureAndBranchPara(CircleNumber,2))=...
NodalAdmittanceMatrix(TopoStructureAndBranchPara(CircleNumber,1),TopoStructureAndBranchPara(CircleNumber,2))...
-1/(TopoStructureAndBranchPara(CircleNumber,3)+...
j*TopoStructureAndBranchPara(CircleNumber,4));
NodalAdmittanceMatrix(TopoStructureAndBranchPara(CircleNumber,2),TopoStructureAndBranchPara(CircleNumber,1))=...
NodalAdmittanceMatrix(TopoStructureAndBranchPara(CircleNumber,1),TopoStructureAndBranchPara(CircleNumber,2));
end
end
运行结果:
NodalAdmittanceMatrix=
1.0421-8.2429i-0.5882+2.3529i0+3.6667i-0.4539+1.8911i
-0.5882+2.3529i1.0690-4.7274i00
0+3.6667i00-3.3333i0
-0.4539+1.8911i000.9346-4.2616i
Experiment2
BusImpedanceMatrix
1.Objective
•TowriteasimpleprograminMATLAB®forthealgorithmofbusimpedancematrix.
2.Discussion
BusImpedancematrix
Thenode-currentequationofann-buspowersystemcanbewritteninmatrixformas
(1)
Or
(2)
WhereIbusisthevectoroftheinjectedbuscurrents.Vbusisthevectorofbusvoltagesmeasuredfromthereferencenode.Zbusisknownasthebusimpedancematrix.
ZbusCALCULATION
Therearetwomajormethods:
1.InversionofYbus
2.Zbusbuildingalgorithm
3.LUfactorization.
Matrixinversionforverylarge-scalenetworksisveryslowandavoided.Ontheotherhand,theZbusbuildingalgorithmistheacceptablemethodforlargenetworks.Itismuchfasterandeasiertoupdate.
ZbusBuildingAlgorithm
ThisisaverysystematicwayofformingZbusandallowforeasyimplementationonthedigitalcomputer.
Advantages
1.Easytoimplement
2.Avoidsmatrixinversion
3.ItiseasytohandleZbusmodificationsduetolineswitchingsandchangesinnetworktopology
Solution:
Notation
Theadditionofabranchofimpedancezbfallsinto4categoriesasfollows.
CASE1:
Addingzbfromanewbusptothereferencebus0
Here,
●
willbe
matrix
●Injectedcurrent
willnotchangethebusvoltagesoftheoriginalnetwork
●
Then,
CASE2:
Addingzbfromanewbusptoanexistingbusk
Here,
●
willbe
matrix
●Injectedcurrent
willchangethebusvoltagesoftheoriginalnetwork
●Injectedcurrentatbuskbecomes
●
Then,
SummaryofCase2
CASE3:
Addingzbfromanexistingbusktothereferencebus0
Here,
●
willbe
matrix
●ThisisaspecialcaseofCASE2exceptthat
Then,
SinceVp=0,thelastrowcanbeeliminatedbyKronreduction(onekindofmathematicsmethod)toyieldann×nmatrixas
SummaryofCase3
•ProceedasinCASE2
•Eliminatethelastrow
CASE4:
Addingzbfromtwoexistingbusesjandk
Here,
●
willbe
matrix
●Branchcurrent
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