人教版小学数学六年级期末复习重点难点知识点.docx
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人教版小学数学六年级期末复习重点难点知识点.docx
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人教版小学数学六年级期末复习重点难点知识点
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Baiduknows[education/Science]primaryschooleducation
PEPedition,primarymathematics,gradesix,finalreview,keypoints,difficulties,knowledgepoints
Views:
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50|questiontime:
2009-12-1219:
20|questionger:
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Tolist,torecite,torefine.Problemsupplement:
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1numberpercopy=total
Thetotalnumberofcopiesper=.
Thetotalnumberofcopiesofeachnumber=.
21multiples*multiples=multiples
Afewtimes,1timestimes=
Afewtimes,ratio=1times
3speedxtime=distance
Distance/speed=time
Time=distance/speed
4unitprice=quantity=totalprice
Price/price=number
Thetotalnumberof83019=price
5workefficiency*workinghours=workamount
Thetotalamountofwork,workefficiency=workingtime
Thetotalamountofwork,worktime=workefficiency
6addendaddend=+and
Anda=otheraddendaddend
7-meiosisdifference=minuend
Minuend-difference=meiosis
Poor+=subtrahendminuend
8factorXfactor=product
Product,afactor=anotherfactor
9dividend,divisor=Business
Dividend,divisor=Business
Quotient*divisor=divisor
Mathematicalformulasforelementaryschoolmathematics
1squares
Cperimeter,Sarea,asidelength
Circumference=sidelength*4
C=4a
Area=sidelength*sidelength
S=a*a
2.
V:
volumea:
edgelength
Surface=edgelengthxxx*6
Stable=axa*6
Volume=edgelengthxedgelongxedgelength
V=a*a*a
3rectangle
Cperimeter,Sarea,asidelength
Circumference=(length+width)*2
C=2(a+b)
Area=length*width
S=ab
4cuboid
V:
volumes:
areaa:
long,b:
width,h:
height
(1)surfacearea(length*width+length*height+width*height)*2
S=2(ab+ah+bh)
(2)volume=**width*height
V=abh
5triangle
Sareaa,bottomhhigh
Bottomarea=xheight/2
S=ah/2
Triangleareahigh=x2/bottom
Trianglearea=x2/high
6parallelogram
Sareaa,bottomhhigh
Area=base*height
S=ah
7trapezoid
Sareaa,bottomB,bottomhhigh
Area=(+downonthebottomend)*/2
S=(a+b)*H/2
8round
SC-d=r=diameter,perimeterarearadius
(1)==2***perimeterdiameterpi*radius
C=IId=2IIR
(2)***area=radiusradius
9cylinder
V:
volumeh:
highS;bottomarear:
;baseradiusc:
;bottomperimeter
(1)thesidearea=thecircumferenceofthebottom*high
(2)surfacearea=sidearea+basearea*2
(3)volume=basearea*height
(4)=2/Xvolumesidearearadius
10cone
V:
volumeh:
highS;basearear:
bottomradius
Volume=bottomareaxheight/3
Thetotal,thetotalnumberofcopies=averagenumber
Equationofsumanddifference
(+anddifference)830192=number
(andpoor)830192=decimal
Doublingproblem
And(1=decimalmultiples).
Decimal=multiple=largenumber
(orsum=decimal=largenumber)
Differenceproblem
(1/differencemultiples)=decimal
Decimal=multiple=largenumber
(ordecimal+difference=largenumber)
Treeplantingproblem
1,theproblemoftreeplantingonnonclosedlinescanbedividedintothefollowingthreecases:
Ifanonclosedlineatbothendsareplantingtrees,so:
Number=numberof+1/1=lengthspacing
*(1=lengthspacingnumber)
Fulllength(1/spacing=number)
Ifyouwanttoplanttreesintheendofnonclosedline,theotherendisnotplanting,so:
Number=number=length/spacing
Length=xnumberofrows
=length/numberofrows
Ifbothendsinnonclosedlinearenotplantingtrees,so:
Numbersectionnumber=-1/1=lengthspacing
*(number=lengthspacing+1)
=length/spacing(number1)
2thenumberoftreesonclosedlinesisasfollows
Number=number=length/spacing
Length=xnumberofrows
=length/numberofrows
Profitandloss
(profit+loss),thetwodistributionofthedifferencebetweenthenumberofcopiesinthedistributionof=
(largesurplus-smallsurplus)/twodistributionofthedifferencebetweenthenumberofcopiesinthedistributionof=
(burned-asmalllossoftwotimes),thedifferencebetweenthenumberofcopiesisassignedtoparticipateinthedistributionofthe
Encounterproblem
Encounterdistance=speedandXmeetingtime
Meettime=distance/speedandmeet
Thespeedanddistance,theencountertime=meet
Catchupwithproblems
Trackingdistance=speeddifference*trackingtime
Chaseandchaseanddistance/time=speeddifference
Thespeeddifferenceanddistance=chasechaseandtime.
Flowproblem
Downstreamvelocity=hydrostaticvelocity+flowvelocity
Countercurrentvelocity=hydrostaticvelocity-flowvelocity
Hydrostaticspeed=(downstreamvelocityandvelocity),2
Flowrate=(downstreamspeedvelocity),2
Concentrationproblem
Theweightofthesolute+theweightofthesolvent=theweightofthesolution
Theweight,theweightofthesolutesolutionx100%=concentration
Weightofsolution=concentration=soluteweight
Theweight,concentrationofsolutesolution=weight
Profitanddiscountproblems
Profit=sellingprice-cost
Therateofprofit,profit=costX100%=(sold/cost1)*100%
Amountoffluctuation=principal*ChangePercentage
Theactualpricediscount,theoriginalpricex=100%(<1discount)
Interest=principal*interestrate*time
Aftertaxinterestrates***=principaltime(120%)
1,100ml(1.5cm3)=M=().
1500DM3=(M3)
2,acylindricalbottomdiameteris4cm,10cmhigh,itssideareais()squarecentimeter,volumeis()cubiccentimeter.
3,dosomecylindricalironpipe,howmanyironsheetsarerequired,thatis,toaskforit.Askinghowmuchwaterthepipecanholdisaskingforit.
5.Digacylindricalpoolontheground.Thedepthofthepoolis4meters.Thediameteris6meters.Thepoolcoversanareaofsquaremetersandneedscubicmetersofearth.
6.Spreadthesidesofacylindertogetasquare.Theradiusofthebottomofthiscolumnis2cm,andtheheightofthecylinderis()cm,itsvolumeis()cubiccentimeter.
Two,goodreferee.(10points)
1,thelateralexpansionofthecylindercangetarectangle,thelengthofthisrectangleisequaltothecircumferenceofthebottomofthecylinder,andthewidthisequaltotheheightofthecolumn.()
2.Acylinderwitharadiusof2meters.Itsbottomcircumferenceisequaltoitsbasearea.()
3,thebrokenlinestatisticalchartismorelikelytoseetherelationshipbetweenthepartsandthewhole.()
Three.Writetheserialnumberofthecorrectanswerinbrackets(10points)
1,suchashighattheendofacylindrical,square,rectangularvolumecomparison,()
A.cubecuboidB.largevolume;largevolume;
C.cylindersarelarge,asbigasD..
2,theradiusandheightofthebottomofthecylinderareenlarged3times,anditsvolumeenlargementismultiples
A.3,B.6,C.9,D.27
3,withapieceof28.26cmlong,15.7cmwiderectangularironsheet,shouldbeequippedwithadiameter()cmofcircularironsheet,youcanmakeavolumeofthelargestcontainer.
A.2.5B.4.5C.5D.9
Four,solvetheproblem
1,acylindricalpool,thebottomsurfaceradiusof3meters,thepoolheightof1.5meters,thepoolcanholduptohowmanytons(1cubicmetersofwaterweighing1tons)
2,acapofcylindricalmetalbucket,50cmhigh,thebottomdiameterof30cm,thebucketabouttoomuchiron?
(heretainedinteger)
3,hada1.5meterlongcylindricalwood,sawedoff4decimeterlongafterthesurfaceareadecreasedby50.24squaredecimeter.What'stheoriginalvolumeofthispieceofwood?
4,theinternaldiameterofthewaterpipeis2centimeters,thewaterflowrateofthepipeis8centimeterspersecond,howmanyliterscanthewaterflowin5minutes?
6,aworkshoptoproduce5radiusof0.6meters,20metershighcylindricalironpipe,andinitsappearancepaintedantirustpaint.By0.3kilogramspersquaremeterwithantirustpaint,howmanykilogramsshouldbeusedwithantirustpaint?
(retainadecimalnumberinoneway)
First,determinetheproblem(eachquestion1pointstotalof5points)
1.100tonsofpeanutkernelscanoil38tons,peanutoilyieldis38%tons().
Two
3.tworectangularbodiesofequallength,theymustbeequalinlength,width,height
Four
5.thereciprocalofallnaturalnumbersislessthan1.()
Two,RadioButtonList(each1pointsonlyatotalof5points)
One
2.askhowmuchwateraglassfishtankcanhold,thatis,askfortheglassfishtank[...]
A.surfaceareaB.
VolumeC.,volumeD.,materialarea
3.UncleLi'stimetoprocessaparthasbeenreducedfrom10minutesto8minutes,andhisworkefficiencyhasbeenincreased
A.80%B.25%C.20%D.125%
Four
A.ishigherthanB,B.islowerthanB,C.isequaltoB.
5.a15book,morethanB5,Bthenumberofmorethanafewpercentofcorrecttypeis[]?
Three,fillintheblanks(2pointseachdayatotalof20points)
(1.)a1cubicdecimetercubecanbeplacedtogrow5wideand3decimeter
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