二级C语言上机模拟参考答案1.docx
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二级C语言上机模拟参考答案1.docx
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二级C语言上机模拟参考答案1
参考答案
一、填空题
1.
(1)double
(2)f1(3)f2
2.
(1)structstudent
(2)n-1(3)a[i].name,a[j].name
3.
(1)0
(2)x[i]/N(3)j++
4.
(1)k
(2)N(3)a[k][i]
5.
(1)'0'
(2)s++(3)ctod(a)+ctod(b)
6.
(1)0
(2)n(3)(t*t)
7.
(1)j
(2)0(3)i++
8.
(1)N
(2)k(3)ss[i]
9.
(1)a
(2)b.name(3)score[i]
10.
(1)[M]
(2)N(3)0
11.
(1)t,s
(2)s[i](3)0
12.
(1)j
(2)k(3)p
13.
(1)999
(2)t/10(3)x
14.
(1)48
(2)s++(3)sum
15.
(1)h->next
(2)p->next(3)>=
16.
(1)structstudent*
(2)a->score[i](3)a
17.
(1)s/N
(2)j++(3)-1
18.
(1)n++
(2)0(3)s++
19.
(1)N
(2)i(3)-1
20.
(1)a[0][i]
(2)<(3)x,y
21.
(1)s
(2)--(3)return0
22.
(1)feof(fp)
(2)==sno(3)sizeof(STU)
23.
(1)->sno
(2)->name(3)&t
24.
(1)x[i]/N
(2)j++(3)i++
25.
(1)0
(2)i++(3)2.*i
26.
(1)[N]
(2)i(3)i+1
27.
(1)double
(2)f1(3)f2
28.
(1)FILE*
(2)fclose(fp)(3)fp
29.
(1)1
(2)2*i(3)(-1)
30.
(1)filename
(2)SEEK_END(3)&n
31.
(1)*av
(2)i(3)x[j]
32.
(1)FILE*
(2)fp(3)ch
33.
(1)structstudent
(2)a.name(3)a.score[i]
34.
(1)i
(2)ps[i](3)tp
35.
(1)s[i]
(2)k(3)0
36.
(1)3.
(2)>(3)(2*i+1)
37.
(1)10
(2)0(3)x
38.
(1)0
(2)x(3)t++
39.
(1)0
(2)||(3)1
40.
(1)k
(2)N-1(3)temp
41.
(1)N
(2)break(3)n
42.
(1)p->next
(2)q(3)p->next
43.
(1)h->next
(2)p==0(3)r
44.
(1)0
(2)10*x(3)n/10
45.
(1)N
(2)substr(3)0
46.
(1)1
(2)s(3)i*10
47.
(1)"rb"
(2)>s[j].sno(3)fwrite
48.
(1)*s
(2)1(3)k[n]
49.
(1)*s
(2)s++(3)n
50.
(1)NODE*
(2)q(3)r
51.
(1)->sno
(2)->name(3)&t
52.
(1)0
(2)i++(3)2.*i
53.
(1)j++
(2)s[i]=t1[i](3)j
54.
(1)[N]
(2)t[i][j](3)t[j][i]
55.
(1)t=i
(2)i(3)0
56.
(1)next
(2)t->data(3)t
57.
(1)sum=0
(2)t[i][i](3)1
58.
(1)999
(2)t/10(3)x
59.
(1)10
(2)0(3)x
60.
(1)0
(2)10*x(3)n/10
61.
(1)1
(2)j++(3)j
62.
(1)M
(2)<(3)k
63.
(1)*fw
(2)str(3)str
64.
(1)1
(2)i(3)a[p+i]
65.
(1)N
(2)k(3)ss[i]
66.
(1)3.
(2)>(3)(2*i+1)
67.
(1)s[i]
(2)'9'(3)*t=n
68.
(1)a[i]
(2)a[j](3)a[j]
69.
(1)0
(2)x(3)t++
70.
(1)i++
(2)m(3)m
71.
(1)a[i]%2
(2)a[j](3)j
72.
(1)s[i]
(2)k(3)0
73.
(1)0
(2)n(3)(t*t)
74.
(1)1
(2)s[k](3)c
75.
(1)*n
(2)next(3)head
76.
(1)N
(2)N-1(3)0
77.
(1)N
(2)i(3)-1
78.
(1)structstudent*
(2)a->score[i](3)a
79.
(1)q
(2)next(3)next
80.
(1)(fp)
(2)==(3)fp
81.
(1)&&
(2)0(3)s[j]
82.
(1)structstudent
(2)a.name(3)a.score[i]
83.
(1)1
(2)2*i(3)(-1)
84.
(1)char
(2)ch<='9'(3)'0'
85.
(1)data
(2)next(3)head
86.
(1)0
(2)n(3)head,ch
87.
(1)x
(2)p(3)s
88.
(1)STYPE
(2)FILE(3)fp
89.
(1)0
(2)j--(3)j
90.
(1)t[][N]
(2)i=0;i 91. (1)0 (2)0(3)c 92. (1)a (2)b.name(3)score[i] 93. (1)[M] (2)N(3)0 94. (1)"r" (2)fs(3)ft 95. (1)1 (2)s(3)i*10 96. (1)fp (2)fclose(fp)(3)fname 97. (1)structstudent (2)n-1(3)a[i].name,a[j].name 98. (1)n/2 (2)i(3)a[n-i-1] 99. (1)*a (2)2(3)i+1 100. (1)N (2)substr(3)0 二、改错题 1. (1)char*fun(char*s,char*t) (2)ss++;(3)tt++; 2. (1)q=p+i; (2)while(q>p) 3. (1)doublefun(intm) (2)for(i=100;i<=m;i~1+=0) 4. (1)for(i=strlen(t)-1;i;i--) (2)if(t[j]>t[j+1]) 5. (1)voidfun(char*s,int*a,int*b) (2)++(*a); (3)++(*b); 6. (1)for(i=0;str[i];i++) (2)if(substr[k+1]==0) 7. (1)for(i=2;i<=m;i++) (2)y-=1.0/i/i; 8. (1)intk=0; (2)while(*p||*q) 9. (1)s[j++]=s[i]; (2)s[j]=0; 10. (1)t=1; (2)return(2*s); 11. (1)if(i%k==0) (2)if(k>=i) 12. (1)while(i (2)if(*a) 13. (1)voidfun(longs,long*t) (2)while(s>0) 14. (1)if((k%13==0)||(k%17==0)) (2)} 15. (1)p=h->next; (2)p=p->next; 16. (1)char*fun(char(*sq)[M]) (2)returnsp; 17. (1)#include"stdio.h" (2)upfst(char*p) 18. (1)t+=s[k]; (2)*aver=ave; 19. (1)a2=k/10; (2)returni; 20. (1)intfun(int*x,int*y) (2)t=*x;*x=*y;*y=t; 21. (1)doublefun(intn) (2)c=a;a+=b;b=c; 22. (1)n=strlen(aa); (2)ch=aa[i]; 23. (1)doublefun(doublea,doublex0) (2)if(fabs(x1-x0)>0.00001) 24. (1)num[k]=0; (2)switch(*s) 25. (1)voidfun(char*s,char*t) (2)t[2*d]=0; 26. (1)aa[i]=m%k; (2)printf("%d",aa[i-1]); 27. (1)p=h->next; (2)p=p->next; 28. (1)t=(STU*)calloc(sizeof(STU),m); (2)t[k]=b[j]; 29. (1)k++; (2)if(m==k) 30. (1)p=(NODE*)malloc(sizeof(NODE)); (2)returnh; 31. (1)floatfun(intn) (2)for(i=2;i<=n;i++) 32. (1)s[j++]=s[i]; (2)s[j]=0; 33. (1)if(p==n)return-1; (2)a[i]=a[i+1]; 34. (1)doublefun(intn) (2)returnsum; 35. (1)while(*w) (2)if(*r==*p) 36. (1)doublefun(intn) (2)s=s+(double)a/b; 37. (1)if(n==0) (2)result*=n--; 38. (1)inti,sl; (2)t[i]=s[sl-i-1]; 39. (1)t-=1.0/i; (2)returnt; 40. (1)fun(inta[][M],intm) (2)a[j][k]=(k+1)*(j+1); 41. (1)sum=0; (2)scanf("%d",&a[i][j]); 42. (1)while(*s) (2)s++; 43. (1)r=t; (2)if(*r==0) 44. (1)*t=0; (2)if(d%2! =0) 45. (1)fun(intx,inty,intz) (2)returnj; 46. (1)intfun(intn,intxx[][M]) (2)printf("%d",xx[i][j]); 47. (1)p=s; (2)while(*p++); 48. (1)floatfun(intk) (2)returns; 49. (1)intj,c=0;floatxa=0.; (2)if(x[j]>=xa) 50. (1)if(i%2||s[i]%2==0) (2)t[j]=0; 51. (1)doublefun(doublea,doublex0) (2)if(fabs(x1-x0)>0.00001) 52. (1)voidfun(char*s,char*t) (2)t[2*d]=0; 53. (1)for(j=i+1;j<6;j++) (2)*(pstr+i)=*(pstr+j); 54. (1)#defineFU(m,n)((m)/(n)) (2)return(value); 55. (1)while((fabs(t))>=num) (2)t=s/n; 56. (1)fun(char*a) (2)printf("%c",*a); 57. (1)doubler; (2)while(fabs(m-n)>0.001) 58. (1)voidfun(longs,long*t) (2)while(s>0) 59. (1)if(n==0) (2)result*=n--; 60. (1)*t=0; (2)if(d%2! =0) 61. (1)t=a;a=b;b=t; (2)return(b); 62. (1)if(('a'<=tt[i])&&(tt[i]<='z')) (2)tt[i]-=32; 63. (1)voidfun(longs,long*t) (2)sl=sl*10; 64. (1)floatk; (2)if(*c>*a) 65. (1)intk=0; (2)while(*p||*q) 66. (1)doublefun(intn) (2)s=s+(double)a/b; 67. (1)t=*x;*x=y; (2)returnt; 68. (1)switch(g) (2)case1: return1;case2: return1; 69. (1)inti,sl; (2)t[i]=s[sl-i-1]; 70. (1)while((2<=high)&&(n<10)) (2)yes=0;break; 71. (1)fun(intn) (2)if(n==1) 72. (1)while(*w) (2)if(*r==*p) 73. (1)for(i=0;str[i];i++) (2)if(substr[k+1]==0) 74. (1)longs=0,t=0; (2)t=t/10; 75. (1)a=0; (2)if(*r==*p) 76. (1)s=s+(n+1.)/n; (2)returnt; 77. (1)a2=k/10; (2)returni; 78. (1)char*fun(char(*sq)[M]) (2)returnsp; 79. (1)p=j; (2)p=i; 80. (1)n=strlen(aa); (2)ch=aa[i]; 81. (1)for(i=2;i<=m;i++) (2)y+=1.0/i/i; 82. (1)if(p==n)return-1; (2)a[i]=a[i+1]; 83. (1)k++; (2)if(m==k) 84. (1)b[k]=*p; (2)b[k]='';k++; 85. (1)while(*r) (2)*a=*r;a++;r++; 86. (1)for(i=0,t=0;p[i];i++) (2)c[t]=0; 87. (1)longk=1; (2)num/=10; 88. (1)for(i=0;i (2)t[2*sl]=0; 89. (1)doublef(doublex) (2)returns; 90. (1)fun(inta[],intm) (2)elseif(m>a[mid]) 91. (1)doublesum=0.; (2)sum/=c; 92. (1)s[j++]=s[i]; (2)s[j]=0; 93. (1)t=1; (2)return(2*s); 94. (1)if(d%2==0) (2)s/=10; 95.(1n,intxx[][M]) (2)printf("%d",xx[i][j]); 96. (1)for(i=j+1;i (2)p=i; 97. (1)q=p+i; (2)while(q>p) 98. (1)n=*p-'0'; (2)n=n*8+*p-'0'; 99. (1)sum=0; (2)if((i+1)%5==0) 100. (1)fun(intx,inty,intz) (2)returnj; 三、编程题 1.voidfun(char*w,intm) { chara[N]; inti; for(i=0;i while(w[i]){w[i-m]=w[i];i++;} i--;m--; for(;m>=0;m--,i--)w[i]=a[m]; } 2.intfun(STREC*a,STREC*b,intl,inth) { inti,j=0; for(i=0;i { if(a[i].s>=l&&a[i].s<=h) { b[j]=a[i]; j++; } } returnj; } 3.fun(STUa[],STU*s) { inti; *s=a[0]; for(i=1;i { if(a[i].s { *s=a[i]; } } } 4.voidfun(char*ss) { inti=1; while(ss[i-1]&&ss[i]) { if(ss[i]>='a'&&ss[i]<='z')ss[i]+='A'-'a'; i+=2; } } 5.floatfun(floath) { longi=h*1000; if(i%10<5)return(i/10)/100.0; elsereturn(i/10+1)/100.0; } 6.doublefun(doubleeps) { doublei=1,a=1,b=1,c=1,s=0; while(c>=eps) { s+=c; a*=i; b*=2*i+1; c=a/b; i++; } returns*2; } 7.intfun(intscore[],intm,intbelow[]) { inti,j=0,s=0; for(i=0;i s/=m; for(i=0;i { if(score[i] { below[j]=score[i]; j++; } } returnj; } 8.voidfun(char*a) { inti=0,j=0; while(a[i]) { if(j==0&&a[i]! ='*') { j=i+1; } elseif(a[i]! ='*') { a[j]=a[i]; j++; } i++; } a[j]=0; } 9.voidfun(char*a) { inti=0,j=0; while(a[i]) { if(a[i]! ='*') { j=i; break; } i++; } while(a[i]) { a[i-j]=a[i]; i++; } i-=j; for(;j>0;j--) { a[i]='*'; i++; } } 10.voidfun(char*a,intn) { inti=0,j=0; while(a[i]) { if(a[i]! ='*') { j=i; break; } i++; } if(j>n) { while(a[i]) { a[i-j+n]=a[i]; i++; } a[i-j+n]=0; } } 11.voidfun(intx,intpp[],int*n) { inti; *n=0; for(i=1;i<=x;i+=2) { if(x%i==0) { pp[*n]=i; (*n)++; } } } 12.voidfun(char*s,chart[]) { inti=0,j=0; while(s[i]) { if(i%2! =0||s[i]%2==0) { t[j]=s[i]; j++; } i++; } t[j]=0; } 13.voidfun(inta,intb,long*c) { *c=a/10*100+a%10+b/10*10+b%10*1000; } 14.doublefun(intn) { inti; doubles=0; for(i=1;i { if(i%3==0&&i%7==0)s+=i; } returnsqrt(s); } 15.voidfun(int(*s)[10],int*b,int*n,intmm,intnn) { inti,j; *n=0;
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