大一无机化学课本答案docWord文档下载推荐.docx
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Itis.
supposethatamixtureofILH20and560LNH3issolubleinwater..
Itsmassis1,000gramsofwater,sothevolumeofthisammoniasolutionis,
9.Solution:
Inthiscase,thesimplestformis:
(2),
So,・
Thisisthemolecularformula
11.Answer:
becauseCaC12andNaClelectrolyte,CH3C00Hforweakelectrolytes,C6H1206astheelectrolyte,thesolutionoftheconcentrationofthesolute(particle)sizeintheorder:
CaC12>
NaCl>
CH3COOH>
C6H1206,sohighandlowordertofreezingpointC6H12O6>
CaC12.
Answer:
so,
Let'
ssayItakethissolution,1,000grams,andIhaveone
14.
Inthesumoftheformula,
No,becauseit'
stoosmalltobeaccurate
A:
becauseoftheAg+overdose,thepreparationoftheAglaerosoltapeispositive,soitistheanionthatmakesuptheglue.SotheabilitytogettogetheristheorderofmagnitudeK3[Fe(CN).
B:
becauseoftheI-excess,thepreparedAglsoltapeisnegativelycharged.Therefore,itisthecationthatmakesthecoagulationoftheglue.SotheabilitytogettogetherisintheorderofA1C13>
MgS04.
Chapteriiproblemsolving
2.Answer:
(1),sothereis.
(2)theinitialpressureis,
Thevolumeoftheintermediatestateiszero
(3)answer:
because,therefore,
(constantpressureis)
becausethereactionisavailable
⑷
(1)-215-296.8+(-1)(-100)二-411.8
Material-412.
-219-296.8+(-1)(-100)二-416.8
Material-417.
(2)(3)(4)...Soyoucanlookitupinthesameway
thereactionequationis:
8.Answer:
1,2,3,5,4,6
(becauseofthereducedgascomponent)
(becauseoftheincreaseinthegascomponent)
(becausethegascomponentincreases)
(becauseofthereducedgascomponent)
(1)becausethemeltingisanisothermalconstantpressurereversibleprocess,sothereis,
(2)becausegasificationisareversibleprocesssuchasisothermalpressure,sothereis
becausemeltingandboilingarebothisothermalandisostaticequilibriumprocesses,sothereare
becauseboilingisanisothermalconstantpressurereversibleprocess,sothereis,
Theequilibriumstateoffreedomisequaltozero
Itispossibletomakeamistakebymistake,mistake,mistake,mistake.
thehightemperaturespontaneously.
Thelowertemperatureisspontaneous.
Atanytemperature,it'
sspontaneous.
18.Answer:
So,thereactionisnevergoingtohappenspontaneously.
reaction
20.Answer:
Soit'
shigherthan1112
21.Answer:
so,notspontaneousat25°
Creaction.
(2),so,in360°
Ccanoccurspontaneously.
3.
Chapteriiiproblemsolving
(2)
(3)
AfG-394.4-16.5-228.6-228.6
ArG=1x(394.4)+
(2)x(16.5),(228.6)and(197.15)
=1.65KJ,mol,1
ArG=-RTln
3,
Equilibriumtimenovermoles0.0210.0040.004
0.025*0.16二0.16
4HBr(g)+02(g)=2H20(g)+2Br2(g)
(1)therateequationforthereactioniszero
Fromtheexperimentaldataanalysis:
Sotherateequationforthisreactioniszero
(1)therateequationfortheexperimentaldatais:
(3)
Becausethereactionisslow(vissmall)andthetimeisshort,itcanbeassumedthatthereactionisapproximatelyconstantwithintheinterval,so12isproduced
7.Accordingto
Inthecaseofmilk,therateatwhichtheacidreactsisdirectlyproportionaltotherateconstantofdifferenttemperatures,namely
Reaction2so2(g)+02(g)=2S03(g)heateffect
Accordingtothe
Thereare
Thewatchcancalculatethereaction
So,balancemovestotheleft.
Or:
18.
(1)decrease;
(2);
(3)increase;
(4):
(5):
(6):
(7);
(8);
(9);
(10);
(12)remainsthesame.
(1)PC15(g)二PC13(g)+C12(g)
Theinitialmolenumberis2,0,0
Balancethenumberofmoles0.5,1.5,1.5
Theconcentrationofeachcomponentinequilibriumis:
(2)whensettobalance,thedecompositionPC15isxmoles.
PC15(g)二PC13(g)+C12(g)
Theinitialnumberofmolesis2,0,1.0
Balancethenumberofmoles2.0minusx,x,x,andx
22.
TheinitialMohris0.20.20
TheinitialMohris0.2minusx0.2minusx2x
12pyrolysisratefor
25.Solution:
Chapter5.Problemsets
A.2
A.3
A.4
A.5
A.6
A.7
"
Eight
A.13.
Thechangeinthenumberof1,1,2,1,3,4,1,3,4,1,3,4,1,3,4,1,3,4
(1)batteryreaction:
(2)batteryreaction:
AgCl(S)+e=+Cl-
(3)electroderesponse:
(4)negativepoles:
Thepositive:
Electromotiveforce:
Originalbatteryreaction:
8.1negative:
Electromotiveforce
Cellresponse:
2negative:
Batteryreaction:
Ce4+Fe2+++Ce3+
Negative3:
2H++2e二H2
Thepositivepole:
Cr2072-++6e=2Cr3++7H20
ElectromotiveforceV
Thebatteryreactionis:
Cr2072-++++3112
Question15:
(2)positivepole:
negativepole:
(3)batteryreaction:
(5)inasolution,itdecreases,causingtheelectromotiveforcetorise.Ifyouaddammoniatothesolution,it'
sgoingtogodown,
It'
scausingtheelectricforcetogodown.
Problem22:
positiveandnegative
Sothereare
Becauseitcanbethoughtofastheanodeandcompositionofthebattery:
Chapter6answerstheatomicstructure
2.
(1)
Bycalculation,thevolatilityofthemacroobjectissosmallthatitcanbeignored.
6.
(1)reasonable
(2)unreasonable.BecauseLcan,tbeequalton,L<
nand>
二ointeger.
(3).
⑷.
(5)unreasonable.BecauseL=0
(6)it'
snotreasonablebecauseLcan,tbegreaterthann
Thesevenelectronsoftheatomarearrangedinones22s22pxl2pyxl2pyxl2pzl
Therefore,itsquantumcombinationis1S2(1,0,0,1/2)(1,0,0,-1/2).
2S2(2,0,0,1/2)(2,0,0,-1/2)
2P3(2,0,1/2)(2,1,1,1/2)(2,1,1,1/2)(1,1,1,1/2)(1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,
Or2,1,0,minus1/2,2,1,minus1/2,2,1,minus1,minus1/2.
9.Na:
1s22s22p63sl
TheISelectronvalidnuclearcharge=11-=11-0.301=10.70
2Selectrons=11-=11-=11-20.85-70.35二6.85(2S2Pisthesamegroup)
33Selectrons二11-二11-二11-80.85-21二2.2(2S2Pisthesamegroup)
Formulti-electronatoms,whenthemainquantumnumbern=4,therearefourenergylevels,namely4S,4P,4Dand4f.Theycorrespondtothenumberoforbitals,1,3,5,7.Themaximumnumberofelectronsyoucanholdis2n2二242-32-2(1+3+5+7)
Forhydrogen,theE4s,>
E3dbecauseit'
sasingleelectronsystem,energylevelsareonlyrelatedtothenumberofquantumNumbers.
InthecaseofK,becauseofthedrillingeffectandshieldingeffect,thereisanenergylevelcrossing,itsE3d>
E4s
2S[Ar]3d54S2
[Xe]4fl45dlO6Sl,4f145dl06S26P6
13.
(1)errorsBecauseoftheAngleoftheatomicorbitalpartofthegraphicalrepresentationistheelectrondistributionoutsidethenucleusdifferentspatialorientationofrisk,notrepresenttheactualmovementoftheelectrons.
(2)theerrorintheNshell(principlequantumnumber二4)thereare4s,4p,4d,4f,atotaloffourenergylevel,thecorresponding1hc-positieatomicorbitalisatotalof16,oftheprincipalquantumnumberN=1,onlyIls,canaccommodatetwooppositespinelectronics.
(3)correctbecausethehydrogenatomisasingleelectronicsystem,thereisnointerleavingphenomenon.
(4)errorbecausehydrogenisasingleelectronicsystemwithouttheshieldingofelectrons.
Cu2+[Ar]3dl+[Ar]3d5
Pb2+[Xe]4fl45dlO6S2-[Ne]3S23P6
(1)24
(2)[Ar]3d54sl(3)3d54sl
(4)thefourthperiod;
VI.B;
Cr03
Whenn>
4,it'
stheEns<
E(n-1)d
Sowhenyoucompletethensandnporbitals,therestoftheelectronsaregoingtohavetofillintheE(n+1)sorbital.
Soyoucan,tfilltheouterlayerwithdelectrons,soyoucanonlyhaveuptoeightelectronsintheouterlayeroftheatomicorbital.Similarly,duetotheEns<
Ef(n-2),whiletheelectronstofillafterthe(n-1)dorbitals,willgiveprioritytofillintheE(n+1)snotenterE(n+1)forbit,sothetimecouldnotfillfelectronsintheouter,therefore,theatomicorbitalcanmorethan18timesontheouterelectrons.
(1)ABCisAmetal
Itispossibletoinfertheirvalencestructurefromthesetupconditions:
4S1,Z=19potassium;
B:
4S2.Z=20
C:
3dl04s2,Z=30zinc;
D:
4S24P5,Z=35bromo
(2)DA+,Br-andK+
(3)AOHisthestrongest
(4)BD2istheioniccompoundofCaBr2
21.
Theeighthcycleelementisthemostavailablenumberofelectronsintheeighthlevelgroup,whichis
8S25gl86f147dl08p6,50electrons,sothereare50elementsintheeighthcycle.
Theelectronicstructureoftheelementis[118]8S25gl(theatomicnumberoftheseventhcycleofararegas),sotheatomicnumberoftheelementis121.(note:
E5g>
E8scannotbedeterminedbyn+0.7L)
Theatomicelectronlayerofelement100is[Rn]7S25f146dl07p2
Sothiselementisthefourthperiodoftheseventhcycle
Sc>
Ca:
TheSr<
Ba;
K>
Ag
Fe2+>
Fe3+;
Pb>
Pb2+;
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