MATLABLE习题文档格式.docx
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MATLABLE习题文档格式.docx
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3
1
6
1
4
7
4*A^2-3*B^2
42
21
38
40
19
46
33
56
A*B
-2
-1
0
8
-4
2
B*A
4
0
来源:
(-MATLAB
程序设计与应用(刘卫国版)习题答案1-2_zdld_新浪博客
2
A*B-B*A
-2
-6
2.B=inv(inv(A)-eye(3))*6*eye(3)
B=
3.A=inv(2*eye(4)-C^(-1)*B)*C^(-1)
A=A'
A=
4.>
A=[2-1
-12];
B=[0-2;
-20];
X=(B+2*A)/2;
X=
5.a=[2-302;
1521;
3-11-1;
4122];
b=[8;
2;
7;
12];
X=a\b;
3.0000
0.0000
-1.0000
1.0000
6.p=[31247081];
x=roots(p)
x=
-3.8230
-0.5275+0.8497i
-0.5275-0.8497i
0.5007+0.6749i
0.5007-0.6749i
-0.1234
7.a=[31247081];
b=conv([1-3],[1050]);
[div,rest]=deconv(a,b)
div=
52
rest=
103
55
788
习题3:
1.
symsxf
f=limit((cos(sqrt(x)))^(pi/x),x,0,'
right'
)
f=exp(-1/2*pi)
2.
f=limit((3*sin(x)+x^2*cos(1/x))/((1+cos(x))*log(1+x)),x,0)
f=3/2
3.
f=limit((sqrt(4*x^2+x-1)+x+1)/sqrt(x^2+sin(x)),x,-inf)
f=1
symsxyf
f=limit(limit((x^2+y^2)^(x^2*y^2),x,0),y,0)
f=1
5.
y=(tan(sqrt(x+sqrt(x+sqrt(2*x)))))^2
y=tan((x+(x+2^(1/2)*x^(1/2))^(1/2))^(1/2))^2
f=diff(y)
f=
tan((x+(x+2^(1/2)*x^(1/2))^(1/2))^(1/2))*(1+tan((x+(x+2^(1/2)*x^(1/2))^(1/2))^(1/2))^2)/(x+(x+2^(1/2)*x^(1/2))^(1/2))^(1/2)*(1+1/2/(x+2^(1/2)*x^(1/2))^(1/2)*(1+1/2*2^(1/2)/x^(1/2)))
6.
y=(cos(x^2))*(sin(1/x))^2
y=cos(x^2)*sin(1/x)^2
-2*sin(x^2)*x*sin(1/x)^2-2*cos(x^2)*sin(1/x)*cos(1/x)/x^2
7.
f=int(sqrt(sin(x)-(sin(x))^3),'
x'
0,pi)
f=4/3
8.
f=int(1/x*sqrt((x+1)/(x-1)))
((1+x)/(x-1))^(1/2)*(x-1)/((1+x)*(x-1))^(1/2)*(-atan(1/(x^2-1)^(1/2))+log(x+(x^2-1)^(1/2)))
9.
f=dsolve('
D2y+4*Dy+4*y=exp(-2*x)'
'
1/2*x^2*exp(-2*x)+C1*exp(-2*x)+C2*exp(-2*x)*x
10.
x^2*Dy+x*y=y^2'
y
(1)=1'
f=2*x/(1+x^2)
习题4:
A=[1240510112131];
plot(A)
程序设计与应用(刘卫国版)习题答案3-4_zdld_新浪博客
(1)
t=[0:
0.01:
2*pi];
x=sin(t);
y=cos(t);
plot(x,y)
axis([-1.51.5-1.51.5])
%限定x轴和y轴的显示范围
gridon
axis('
equal'
(2)
t=0:
0.1:
2*pi;
z=x+y*i;
plot(z)
axisequal
3.已知伏安曲线为U=IR,R分别为1欧姆,5欧姆,10欧姆,20欧姆。
(1)在一张图上画出I在(0-2Π)范围内的U曲线,
(2)添加标题“伏安曲线U=IR”
(3)添加横纵座标的单位“安培”,“伏特”;
(4)添加标出每条线代表的方程。
I=0:
pi/20:
R1=1.0;
R2=5.0;
R3=10.0;
R4=20.0;
U1=I*R1;
U2=I*R2;
U3=I*R3;
U4=I*R4;
plot(I,U1,I,U2,I,U3,I,U4);
title('
伏安曲线U=IR'
);
xlabel('
安培'
ylabel('
伏特'
legend('
U=I'
U=5I'
U=10I'
U=20I'
4.file---importdata---4---A4
x=A4(:
1);
y=[A4(:
2)A4(:
3)];
bar(x,y)
5.A=[1111111
1222221
1223221
1111111];
bar(A)
6.x=-1:
1;
y=-1:
[X,Y]=meshgrid(x,y);
Z=X.^2+Y.^2;
surf(X,Y,Z);
7.[X,Y,Z]=ELLIPSOID(0,0,0,2,3,4);
surf(X,Y,Z)
view([001])
view([010])
totrySPHEREandCYLINDERyourself
MATLAB
程序设计与应用(刘卫国版)习题答案5
(2009-09-3009:
15:
22)
转载
标签:
教育
functionp=excise0501(x1,x2)
x1=-1:
x2=-1:
%[X,Y]=meshgrid(x1,x2);
fori=1:
201
forj=1:
ifx1(i)+x2(j)>
1.0,
p(i,j)=0.5457*exp(-0.75*x2(j)^2-3.75*x1(i)^2-x1(i)*1.5);
elseifx1(i)+x2(j)<
=1.0&
x1(i)+x2(j)>
-1.0,
p(i,j)=0.7575*exp(-x2(j)^2-6.0*x1(i));
elseifx1(i)+x2(j)<
=-1.0,
p(i,j)=0.5457*exp(-0.75*x2(j)^2-3.75*x1(i)^2+x1(i)*1.5);
end
end
surf(x1,x2,p);
2.functionFibonacci1
a
(1)=1;
a
(2)=1;
i=2;
whilei<
20
a(i+1)=a(i-1)+a(i);
i=i+1;
i,a,
3.functionS=excise0503(a,b)
a=0.0;
b=1.0;
dx=linspace(a,b,1001);
h=(a+b)/1000;
S=0.0;
fori=1:
1000
S=S+(sin(dx(i))+sin(dx(i+1)))*h/2;
S
4.functionf=excise0504(x)
ifnargin==0,x=0.5;
end;
ifabs(x)>
=1
break
f=x;
k=1;
u=1;
whilenorm(u,1)>
u=factorial(2*k)*x^(2*k+1)/(2^(2*k)*factorial(k)^2*(2*k+1));
f=f+u;
k=k+1;
f
5.functionn=excise0505
n=1;
m=1;
fori=2:
1:
9
ifmod(i,2)~=0
m=i;
n=[n,m];
[x,y]=size(n);
n=n(2:
y);
%n;
fori=10:
99
m=fix(i/10)+mod(i,10);
ifmod(m,2)~=0
n=[n,i];
fori=100:
999
m=fix(i/100)+fix(mod(i,100)/10)+mod(i,10);
m=fix(sqrt(999));
y
forj=2:
m
ifmod(n(i),j)==0&
j~=n(i)
n(i)=2;
p=1;
ifn(i)~=2
p=[p,n(i)];
n=p;
n
functionexcise0506
n=input('
Pleaseinputn='
W=[232425];
student(i).geometry=input('
Pleaseinputgeometry='
student(i).math=input('
Pleaseinputmath='
student(i).physics=input('
Pleaseinputphysics='
student(i).english=input('
Pleaseinputenglish='
student(i).chinese=input('
Pleaseinputchinese='
student(i).chemistry=input('
Pleaseinputchemistry='
student(i).total=student(i).geometry*W
(1)+student(i).math*W
(2)...
+student(i).physics*W(3)+student(i).english*W(4)...
+student(i).chinese*W(5)+student(i).chemistry*W(6);
student(i).total=student(i).total/6
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