C语言程序设计现代方法第二版习题答案CProgrammingAModernApproachWord文件下载.docx

C语言程序设计现代方法第二版习题答案CProgrammingAModernApproachWord文件下载.docx

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Valueofj:

j）;

Valueofk:

k）;

Valueofx:

%g\n"

x）;

Valueofy:

y）;

Valueofz:

z）;

WhencompiledusingGCCandthenexecuted,thisprogramproducedthefollowingoutput:

5618848

0

6844404

3.98979e-34

9.59105e-39

Thevaluesprinteddependonmanyfactors,sothechancethatyou'

llgetexactlythesenumbersissmall.

5.[was#10]（a）isnotlegalbecause100_bottlesbeginswithadigit.

8.[was#12]Thereare14tokens:

a,=,（,3,*,q,-,p,*,p,）,/,3,and;

.

AnswerstoSelectedProgrammingProjects

4.[was#8;

modified]

floatoriginal_amount,amount_with_tax;

Enteranamount:

"

）;

scanf（"

%f"

&

original_amount）;

amount_with_tax=original_amount*1.05f;

Withtaxadded:

$%.2f\n"

amount_with_tax）;

Theamount_with_taxvariableisunnecessary.Ifweremoveit,theprogramisslightlyshorter:

floatoriginal_amount;

original_amount*1.05f）;

Chapter3

2.[was#2]

（a）printf（"

%-8.1e"

（b）printf（"

%10.6e"

（c）printf（"

%-8.3f"

（d）printf（"

%6.0f"

5.

respectively.

[was#8]Thevaluesofx,i,andywillbe12.3,45,and.6,

1.[was#4;

intmonth,day,year;

Enteradate（mm/dd/yyyy）:

scanf（"

%d/%d/%d"

month,&

day,&

year）;

Youenteredthedate%d%.2d%.2d\n"

year,month,day）;

3.[was#6;

intprefix,group,publisher,item,check_digit;

EnterISBN:

%d-%d-%d-%d-%d"

prefix,&

group,&

publisher,&

item,&

check_digit）;

GS1prefix:

prefix）;

Groupidentifier:

group）;

Publishercode:

publisher）;

Itemnumber:

item）;

Checkdigit:

check_digit）;

/*Thefiveprintfcallscanbecombinedasfollows:

%d\nGroupidentifier:

%d\nPublishercode:

%d\nItemnumber:

%d\nCheckdigit:

prefix,group,publisher,item,check_digit）;

*/

}

Chapter4

2.[was#2]NotinC89.Supposethatiis9andjis7.Thevalueof（-i）/jcouldbeeither—1or—2,dependingontheimplementation.Ontheotherhand,thevalueof-（i/j）isalways—1,regardlessoftheimplementation.

InC99,ontheotherhand,thevalueof（-i）/jmustbeequaltothevalueof-（i/j）.

9.[was#6]

（a）638

（b）321

（c）2-13

（d）000

13.[was#8]Theexpression++iisequivalentto（i+=1）.Thevalueofbothexpressionsisiaftertheincrementhasbeenperformed.

2.[was#4]

intn;

Enterathree-digitnumber:

%d"

n）;

Thereversalis:

%d%d%d\n"

n%10,（n/10）%10,n/100）;

Chapter5

2.[was#2]

（a）1

（b）1

（c）1

（d）1

4.[was#4]（i>

j）-（i<

j）

6.[was#12]Yes,thestatementislegal.Whennisequalto5,itdoesnothing,since5isnotequalto-9.

10.[was#16]Theoutputis

onetwo

sincetherearenobreakstatementsafterthecases.

2.[was#6]

inthours,minutes;

Entera24-hourtime:

%d:

hours,&

minutes）;

Equivalent12-hourtime:

if（hours==0）

12:

%.2dAM\n"

minutes）;

elseif（hours<

12）

hours,minutes）;

elseif（hours==12）

%.2dPM\n"

else

hours-12,minutes）;

4.[was#8;

intspeed;

Enterawindspeedinknots:

speed）;

if（speed<

1）

Calm\n"

elseif（speed<

=3）

Lightair\n"

=27）printf（"

Breeze\n"

=47）printf（"

Gale\n"

=63）

Storm\n"

else

Hurricane\n"

6.[was#10]

intcheck_digit,d,i1,i2,i3,i4,i5,j1,j2,j3,j4,j5,first_sum,second_sum,total;

Enterthefirst（single）digit:

%1d"

d）;

Enterfirstgroupoffivedigits:

%1d%1d%1d%1d%1d"

i1,&

i2,&

i3,&

i4,&

i5）;

Entersecondgroupoffivedigits:

j1,&

j2,&

j3,&

j4,&

j5）;

Enterthelast（single）digit:

first_sum=d+i2+i4+j1+j3+j5;

second_sum=i1+i3+i5+j2+j4;

total=3*first_sum+second_sum;

if（check_digit==9-（（total-1）%10））printf（"

VALID\n"

NOTVALID\n"

10.[was#14]

intgrade;

Enternumericalgrade:

grade）;

if（grade<

0||grade>

100）{printf（"

Illegalgrade\n"

return0;

switch（grade/10）{

case10:

case9:

Lettergrade:

A\n"

break;

case8:

B\n"

case7:

C\n"

case6:

D\n"

case5:

case4:

case3:

case2:

case1:

case0:

F\n"

Chapter6

4.[was#10]（c）isnotequivalentto（a）and（b）,becauseiisincrementedbeforetheloopbodyisexecuted.

10.[was#12]Considerthefollowingwhileloop:

while（…）{

continue;

Theequivalentcodeusinggotowouldhavethefollowingappearance:

while（…）{

gotoloop_end;

loop_end:

;

/*nullstatement*/

12.[was#14]

for（d=2;

d*d<

=n;

d++）if（n%d==0）

break;

Theifstatementthatfollowstheloopwillneedtobemodifiedaswell:

if（d*d<

=n）

%disdivisibleby%d\n"

n,d）;

%disprime\n"

n）;

14.[was#16]Theproblemisthesemicolonattheendofthefirstline.Ifweremoveit,thestatementisnowcorrect:

if（n%2==0）printf（"

niseven\n"

intm,n,remainder;

Entertwointegers:

%d%d"

m,&

while（n!

=0）{

remainder=m%n;

m=n;

n=remainder;

Greatestcommondivisor:

m）;

4.[was#4]

floatcommission,value;

Entervalueoftrade:

value）;

while（value!

=0.0f）{

if（value<

2500.00f）

commission=30.00f+.017f*value;

elseif（value<

6250.00f）commission=56.00f+.0066f*value;

20000.00f）

commission=76.00f+.0034f*value;

50000.00f）commission=100.00f+.0022f*value;

500000.00f）

commission=155.00f+.0011f*value;

commission=255.00f+.0009f*value;

if（commission<

39.00f）

commission=39.00f;

Commission:

$%.2f\n\n"

commission）;

6.[was#6]

inti,n;

Enterlimitonmaximumsquare:

for（i=2;

i*i<

i+=2）printf（"

%d\n"

i*i）;

8.[was#8]

inti,n,start_day;

Enternumberofdaysinmonth:

Enterstartingdayoftheweek（1=Sun,7=Sat）:

start_day）;

/*printanyleading"

blankdates"

*/

for（i=1;

i<

start_day;

i++）

/*nowprintthecalendar*/for（i=1;

i++）{printf（"

%3d"

if（（start_day+i-1）%7==0）printf（"

\n"

Chapter7

3.[was#4]（b）isnotlegal.

4.[was#6]（d）isillegal,sinceprintfrequiresastring,notacharacter,asitsfirstargument.

10.[was#14]unsignedint,becausethe（int）castappliesonlytoj,notj*k.

12.[was#16]Thevalueofiisconvertedtofloatandaddedtof,thentheresultisconvertedtodoubleandstoredind.

14.[was#18]No.Convertingftointwillfailifthevaluestoredinfexceedsthelargestvalueoftypeint.

AnswerstoSelectedProgrammingProjects1.[was#2]shortintvaluesareusuallystoredin16bits,causingfailureat182.intandlongintvaluesareusuallystoredin32bits,withfailureoccurringat46341.

2.[was#8]

charch;

Thisprogramprintsatableofsquares.\n"

Enternumberofentriesintable:

ch=getchar（）;

/*disposeofnew-linecharacterfollowingnumberofentries*//*couldsimplybegetchar（）;

%10d%10d\n"

i,i*i）;

if（i%24==0）{

PressEntertocontinue..."

/*orsimplygetchar（）;

5.[was#10]

ctype.h>

intsu